Re: converting a 90ohm sender to a 30ohm sender
Quote:
Originally Posted by fixit-p
I may have interpreted Docvette incorrectly but I think he was going from 30 ohm to 90 ohm and not 90 ohm to 30 ohm. The formula for resistors in series is R=R1+R2 so any resistance placed in series is added to the 90 ohm. But resistors in parallel is R= R1x R2 / R1+R2 so 90 x 47 / 90 + 47 = ~30.87 ohm, but it wont be lineal because at 1/2 tank @ 45 ohm parallel with 47 ohm you get ~23 ohm which is about 3/4 tank on the 30 ohm system.
|
FIXIT-P isn't 90 ohms what we are looking for to convert to the camaro gauge. The total resistance at full should be 90 ohms. I believe Doc said to use a 100 ohm pot.
The pot would go in the sender wire from the variable resistor.
This is starting to make my head hurt LOL
__________________
VetteVet
metallic green 67 stepside
74 corvette convertible
1965 Harley sportster
1995 Harley wide glide
Growing old is hell, but it beats the alternative.
|