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Re: Mechanical speedometer drive solution
22.51Hz * 60s = 1,350.6rpm
(1000rpm/1,350rpm)=0.740 and (60mph/0.740)=81.08mph
I may be able to get the motor spinning and then slow it down to drive the speedometer less than 8mph.
Let’s look at RPM of the electric motor vs. Hz. of the DRAC:
The Chicago Electric slow speed is 133.8rpm.
The formula to find MPH is (1000rpm/133.8rpm)=7.47 and (60mph/7.47)=8.03mph
Let’s rearrange this equation to find rpm:
(60mph/8.03mph) = 7.47 and (1000rpm/7.47) = 133.8rpm
Put this formula into a spreadsheet with the mph and Hz to find the range of RPM for the speedo motor, and create a chart:
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