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07-22-2015, 06:23 PM | #1 |
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Join Date: Sep 2013
Location: Vacaville CA
Posts: 490
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Re: My caster mod (with pictures)
Thanks. I'd be interested to know how many degrees that adds.
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07-22-2015, 11:22 PM | #2 | |
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Join Date: Dec 2009
Location: Kirkland, WA
Posts: 1,302
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Re: My caster mod (with pictures)
Quote:
Assuming 9" between ball joints and a currently vertical spindle, 3.14 * (4.5^2) = 64 (radius of a circle) 360 * (64 * .25) = 1.4 degrees (360 degrees in a circle times the fraction of the circle that is 1/4") So 1" should net about 5.6*, 3/4" would be around 4.2* gain
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1968 LWB C20 / AC / Wood Bed Last edited by crakarjax; 07-22-2015 at 11:35 PM. |
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07-28-2015, 01:56 AM | #3 |
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Join Date: Dec 2009
Location: Kirkland, WA
Posts: 1,302
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Re: My caster mod (with pictures)
I ended up grinding a small flat in the shaft and then drilling with a 5/8" masonry bit. I noticed in the process that I didn't need to sink the hole in the shaft at all on the sides because the locating pin sits flush with the seats as they slope upward -- I think grinding flats for locating would work just fine considering this, since a sunk hole is actually just removing material that doesn't need to be there. Using a cap screw might be a different story though depending on the head depth.
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1968 LWB C20 / AC / Wood Bed |
08-06-2015, 03:21 AM | #4 | |
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Join Date: Sep 2013
Location: Vacaville CA
Posts: 490
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Re: My caster mod (with pictures)
Quote:
Circumference of a 9" circle would be: 3.14 * diameter = 28.26" degrees per inch moved (around that circle) would be 360 / 28.26 = 12.7 This ignores the cosine error, of course, making my calculations a little larger than we'd actually get. So, compared to a vertical spindle... moving 1.0" equals 12.7 degrees caster moving .75" equals 9.5 degrees moving .5" equals 6.35, etc.... |
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