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03-19-2012, 11:20 AM | #1 |
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Why when one turn signal burns out does it double the speed of the other?
Why does this happen?
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03-19-2012, 11:39 AM | #2 |
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Re: Why when one turn signal burns out does it double the speed of the other?
I'll take a shot at explaining it. The flasher has a bi-metallic strip in it that heats and cools to cause the flash. The bulbs are what is considered a "load" on the system. If one bulbs is burned out, causing an open circuit, the flasher does not have to work that load causing it to cycle faster. I'm sure someone like VetteVet can word it better than I just did.
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03-19-2012, 12:15 PM | #3 |
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Re: Why when one turn signal burns out does it double the speed of the other?
I always thought they engineered that in to alert the driver they had a turn signal burned out since you're usually inside the car driving and can't see the turn signals on the outside.
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03-19-2012, 03:14 PM | #4 | |
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Re: Why when one turn signal burns out does it double the speed of the other?
The OEM flasher is a thermal bi-metallic type and the speed of the flasher is dependent on resistance (resistance limits current flow and current flow is what heats up the bi-metal element breaking contact). If you lose one bulb on the left side resistance to ground on that side increases resulting in less current draw causing it to flash slower. The right side does not speed up but rather the left side slows down making it seem like the other side sped up. If you have a short to ground it will cause the flasher to cycle really fast until it fails.
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03-19-2012, 05:17 PM | #5 |
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Location: Sacramento, Calif
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Re: Why when one turn signal burns out does it double the speed of the other?
What year vehicle? It matters.
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